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17p-7=6p^2
We move all terms to the left:
17p-7-(6p^2)=0
determiningTheFunctionDomain -6p^2+17p-7=0
a = -6; b = 17; c = -7;
Δ = b2-4ac
Δ = 172-4·(-6)·(-7)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-11}{2*-6}=\frac{-28}{-12} =2+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+11}{2*-6}=\frac{-6}{-12} =1/2 $
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